Friday 30 October 2009

EU COMPETITION (#2)

Twice a month you will find three questions on the European Union and Europe. The first student answering them correctly will get a small gift. Send your answers to iescampanar09@gmail.com.
Here are this fortnight's questions: 1.-When is Europe Day celebrated each year? 2.-The EU has 23 official languages and has to publish legislation in all of them. Name 10 languages. 3.-What do these common European acronyms and abbreviations STEP ERICA ISBN stand for? --------Easy? Well, lots of luck!!!--
SOLUTIONS:
1.- 9th of May
2.-The European Union has 23 official and working languages. They are: Bulgarian, Czech, Danish, Dutch, English, Estonian, Finnish, French, German, Greek, Hungarian, Irish, Italian, Latvian, Lithuanian, Maltese, Polish, Portuguese, Romanian, Slovak, Slovene, Spanish and Swedish.
3.-Science and Technology for Environment Protection, European Research Institute for Consumers Affairs, International Standard Book Number.

Thursday 29 October 2009

Monday 26 October 2009

WEEK'S PUZZLE 4



PUZZLE 4- from the 27th October to the 1st November(to be collected by the 2nd November)



A FOOTBALL
A polyhedron with the shape of a football has 32 sides: 20 of them are regular hexagons and 12 are regular pentagons, as you can clearly see in the picture above.
How many vertices and edges does this solid have?
SOLUTION:
The football has as many vertices as the pentagons have: 12x5=60. As for the number of edges, which are counted twice, there are as many as the edges of all the polygons: (20x6 + 12x5)/2 = 180/2 = 90.

Wednesday 21 October 2009

LÜNEBURG'S TEAM IN AJKA

To give you an impression of the autumnal colours in Lüneburg at this time of the year our group poses in front of the trees around the school's little pond. From left to right:
Astrid Jacobs, Verena Krüger, Lisa Marie Heinemann, Camilla Kast, Julian Karping, Fynn Hohls, Carlotta Wichmann, René Jenkel.

Monday 19 October 2009

WEEK'S PUZZLE 3

PUZZLE 3- from the 19th to the 25th October (to be collected by the 26th October)



A NUMEROUS FAMILY

The product of my sons’ ages is 1664. The age of the eldest is the double of my youngest son’s age. I am 50 years old myself.
How many sons have I got?
How old are they?


SOLUTION
The factorial decomposition of 1664 is the product of 13 x 2 with exponent 7. Since 13 can be neither the youngest nor the eldest son, the solution is 2 with exponent 3 = 8, 13, and 2 with exponent 4 = 16. Therefore the three sons are: 8, 13 and 16 years old.

LIPNIK'S TEAM IN THE NEXT MEETING

Thursday 15 October 2009

EU Competition

Twice a month you will find three questions on the European Union and Europe. The first student answering them correctly will get a small gift.
Send your answers to iescampanar09@gmail.com
Here are the first three questions:
1.-When did the 5 countries participating in the project join the EU?
2.-Unscrabble the motto of the EU: TUINDE NI YESDRIITV
3.-Do you know which phone number you can dial to ask questions on EU matters in the official EU language of your choice?
Lots of luck!!!
SOLUTION:
1.-Hungary and the Czech Republic in 2004, Spain in 1986, Switzerland does not belong to the EU and Germany from its foundation, being considered the treaty of Rome signed in 1957 as the official date since it established the European Economic Community (EEC) and the European Atomic Energy Community (Euratom).
2.- UNITED IN DIVERSITY
3.- 00 800 5 6 7 8 9 10 11

Sunday 11 October 2009

WEEK'S PUZZLE 2

PUZZLE 2* 12th -18th October (to be collected by the 19th)


AT THE CIRCUS

The most experienced trainer of a circus needs 40 minutes to wash an elephant,
his son doing the same task in 2 hours.
How long will it take them both to wash 4 elephants?
How many elephants will each of them wash?


SOLUTION TO PUZZLE 2

In two hours the son washes one elephant while his father washes 120:40 =3 elephants in the same period of time.

Thus it takes them 2 hours to wash 4 elephants since the son washes 1 while his father washes 3.


*Solution to Puzzle 1 on Tuesday, October the 13th

Friday 2 October 2009

WEEK' S PUZZLE 1

PUZZLE 1 5th -11th October (to be collected by the 12th)

A CHESS GAME

There were 15 players in the latest chess game in which Kazimier Kaczyinski took part following the Swiss variant (all-against-all, once).
The sum of all the points obtained by all the players except Kazimier was: 100 points. How many points did Kazimier get?

Note: 1 point for a win and ½ for a draw, each player.
SOLUTION

First of all we can argue that each person plays against the other 14 players, so the number of games should be 15x14. However, if we do it this way, each game is counted twice. This is why the total number of games is actually (15x14)/2 = 105.
Since each game means 1 point of the total amount, we would have as a result 105 points.
Consequently Kazimier got 105 – 100 = 5 points.